MJD340TF Overview
DC current gain' is equal to the ratio of the collector current to the base current, something like Ic/Ib, and this device has 30 @ 50mA 10V DC current gain.The emitter base voltage can be kept at 3V for high efficiency.Normally, a fuse's current rating refers to how much current it can carry without deteriorating too much, which in this case is 500mA.Breakdown input voltage is 300V volts.Collector current can be as low as 500mA volts at its maximum.
MJD340TF Features
the DC current gain for this device is 30 @ 50mA 10V
the emitter base voltage is kept at 3V
the current rating of this device is 500mA
MJD340TF Applications
There are a lot of ON Semiconductor MJD340TF applications of single BJT transistors.
- Muting
- Inverter
- Driver
- Interface
