KSC5019MTA Overview
The DC current gain is the ratio of the base current to the collector current βdc = Ic/Ib and the DC current gain for this device is 140 @ 500mA 1V.A collector emitter saturation voltage of 500mV ensures maximum design flexibility.When VCE saturation is 500mV @ 50mA, 2A, transistor means Ic has reached transistors maximum value (saturated).Keeping the emitter base voltage at 6V can result in a high level of efficiency.In definition, current rating refers to the maximum current a fuse can carry for an indefinite period without deteriorating too much, and the current rating of this device is 2A.A transition frequency of 150MHz is present in the part.An input voltage of 10V volts is the breakdown voltage.The maximum collector current is 2A volts.
KSC5019MTA Features
the DC current gain for this device is 140 @ 500mA 1V
a collector emitter saturation voltage of 500mV
the vce saturation(Max) is 500mV @ 50mA, 2A
the emitter base voltage is kept at 6V
the current rating of this device is 2A
a transition frequency of 150MHz
KSC5019MTA Applications
There are a lot of ON Semiconductor KSC5019MTA applications of single BJT transistors.
- Inverter
- Driver
- Interface
- Muting