2N6519BU Overview
In this device, the DC current gain is 40 @ 50mA 10V, which is calculated by taking the ratio of the base current to collector current and dividing transistor by two.Saturation of VCE means Ic is at its maximum value (saturated), and VCE saturation (Max) is 1V @ 5mA, 50mA.A high level of efficiency can be achieved if the base voltage of the emitter remains at 5V.As defined by current rating, the maximum current a fuse can carry without deteriorating too much is -500mA for this device.During maximum operation, collector current can be as low as 500mA volts.
2N6519BU Features
the DC current gain for this device is 40 @ 50mA 10V
the vce saturation(Max) is 1V @ 5mA, 50mA
the emitter base voltage is kept at 5V
the current rating of this device is -500mA
2N6519BU Applications
There are a lot of ON Semiconductor 2N6519BU applications of single BJT transistors.
- Interface
- Muting
- Inverter
- Driver
